![]() ![]() bashrc The regex searches for the character string. Grep Regex Example Run the following command to test how grep regex works: grep if. I want to grep the line which has the string 'samba' only. Both the option you gave is not working in my case. Yes I read the grep manual and I am unable to locate the exact switch for grep which i need. Which would also return lines where the second field is 71161.0 or 71.161e3 or 0x115f9 (for GNU awk, you need to pass POSIXLY_CORRECT in the environment for hexadecimal numbers to be considered though). Pearl Compatible Regular Expressions ( PCRE) By default, grep uses the BRE syntax. If youre grepping for a word, you can also use grep -w .![]() Explanation: Your problem is how to cut the right column, because grep only grab the lines which matches your patten. it is : following -d you may change this delimiter to suit future file format. both single quote and the backslash are necessary 2. You can also do numeric comparisons with: awk '$2 = 71161 || $2 = 71072 || $2 = 72617' < mainfile Try this: cat yourfile cut -f1 -d: grep Note: 1.![]() So to guard against that you may want to set LC_ALL to C). For instance on a GNU system in a UTF-8 locale, a POSIX awk would return true for "71161" = "٧١١٦١" because in current versions of those GNU locales, the Eastern Arabic digits collate the same as the Western Arabic (English) equivalents. (Beware that for POSIX awk implementations (not the ones typically found on current Linux distributions though), the = operator applied to strings tests whether the two strings collate the same, which can be different from being equal. 1 01-21-2013 Subbeh Registered User 334, 87 Exclude dash in grep Hi, I must be overlooking something, but I don't understand why this doesn't work. Adding helped to only change the samplename. Or: awk '$2 ~ /^(72617|71072|71161)$/' < mainfile I thought <> could be used to find an exact match, but when I use this, nothing is changed.Thanks in advance - Post updated at 06:33 AM. Awk may be a better choice here: awk 'BEGIN $2 in a' < mainfile Hi This time Im trying to grep for an exact match e.g .bird.pig horse dog dog pig.dog how do I grep for dog only so that a wc -l would result 2 in above case. ![]()
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